# Thread: Trig Problem

1. ## Trig Problem

I need help. I don't know how to solve this problem to find x...

How do I get x?

help please and thank you (:

2. Originally Posted by ninjuhtime
I need help. I don't know how to solve this problem to find x...

How do I get x?

help please and thank you (:
let $h$ = length of the triangles' vertical side

$\tan(15) = \frac{h}{x}$

$x \tan(15) = h$

$\tan(27) = \frac{h}{x-65}$

$(x-65)\tan(27) = h$

since $h = h$ ...

$(x-65)\tan(27) = x\tan(15)$

solve for x

3. x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?

4. Originally Posted by ninjuhtime
x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?
x is distance? at least thats what it shows in ur diagram

5. Originally Posted by firebio
x is distance? at least thats what it shows in ur diagram
yea, haha.

does x = 88 ?
or is my answer wrong...?

6. Originally Posted by ninjuhtime

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?
yea, haha.

does x = 88 ?
or is my answer wrong...?
I got x = 137
88 is wrong because u r not working in radians

7. Originally Posted by firebio
I got x = 137
88 is wrong because u r not working in radians
oh, thank you. (:
no wonder i got it wrong... i'm suppose to use degrees not radians... haha...