Thread: Trig Problem

I need help. I don't know how to solve this problem to find x...


How do I get x?

help please and thank you (:

Originally Posted by ninjuhtime

I need help. I don't know how to solve this problem to find x...


How do I get x?

help please and thank you (:

let $\displaystyle h$ = length of the triangles' vertical side


$\displaystyle \tan(15) = \frac{h}{x} $

$\displaystyle x \tan(15) = h$


$\displaystyle \tan(27) = \frac{h}{x-65}$

$\displaystyle (x-65)\tan(27) = h$


since $\displaystyle h = h$ ...

$\displaystyle (x-65)\tan(27) = x\tan(15)$

solve for x

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?

Originally Posted by ninjuhtime

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?

x is distance? at least thats what it shows in ur diagram

Originally Posted by firebio

x is distance? at least thats what it shows in ur diagram

yea, haha.



does x = 88 ?
or is my answer wrong...?

Originally Posted by ninjuhtime

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?
yea, haha.



does x = 88 ?
or is my answer wrong...?

I got x = 137
88 is wrong because u r not working in radians

Originally Posted by firebio

I got x = 137
88 is wrong because u r not working in radians

oh, thank you. (:
no wonder i got it wrong... i'm suppose to use degrees not radians... haha...