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Math Help - Trig Problem

  1. #1
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    Trig Problem

    I need help. I don't know how to solve this problem to find x...


    How do I get x?

    help please and thank you (:
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  2. #2
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    Quote Originally Posted by ninjuhtime View Post
    I need help. I don't know how to solve this problem to find x...


    How do I get x?

    help please and thank you (:
    let h = length of the triangles' vertical side


    \tan(15) = \frac{h}{x}

    x \tan(15) = h


    \tan(27) = \frac{h}{x-65}

    (x-65)\tan(27) = h


    since h = h ...

    (x-65)\tan(27) = x\tan(15)

    solve for x
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  3. #3
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    x = 88 in radians
    am i right?

    or is it: x = 137.09 in degrees?
    Last edited by ninjuhtime; December 21st 2009 at 07:31 PM.
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  4. #4
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    Quote Originally Posted by ninjuhtime View Post
    x = 88 in radians
    am i right?

    or is it: x = 137.09 in degrees?
    x is distance? at least thats what it shows in ur diagram
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  5. #5
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    Quote Originally Posted by firebio View Post
    x is distance? at least thats what it shows in ur diagram
    yea, haha.



    does x = 88 ?
    or is my answer wrong...?
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  6. #6
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    Quote Originally Posted by ninjuhtime View Post

    x = 88 in radians
    am i right?

    or is it: x = 137.09 in degrees?
    yea, haha.



    does x = 88 ?
    or is my answer wrong...?
    I got x = 137
    88 is wrong because u r not working in radians
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  7. #7
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    Quote Originally Posted by firebio View Post
    I got x = 137
    88 is wrong because u r not working in radians
    oh, thank you. (:
    no wonder i got it wrong... i'm suppose to use degrees not radians... haha...
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