Trig Problem

**ninjuhtime** · Dec 21st 2009, 03:36 PM

I need help. I don't know how to solve this problem to find x...

How do I get x?

help please and thank you (:

**skeeter** · Dec 21st 2009, 04:01 PM

Originally Posted by ninjuhtime

I need help. I don't know how to solve this problem to find x...

How do I get x?

help please and thank you (:

let $h$ = length of the triangles' vertical side

$\tan(15) = \frac{h}{x}$

$x \tan(15) = h$

$\tan(27) = \frac{h}{x-65}$

$(x-65)\tan(27) = h$

since $h = h$ ...

$(x-65)\tan(27) = x\tan(15)$

solve for x

**ninjuhtime** · Dec 21st 2009, 06:06 PM

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?

**firebio** · Dec 21st 2009, 07:46 PM

Originally Posted by ninjuhtime

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?

x is distance? at least thats what it shows in ur diagram

**ninjuhtime** · Dec 21st 2009, 07:54 PM

Originally Posted by firebio

x is distance? at least thats what it shows in ur diagram

yea, haha.

does x = 88 ?
or is my answer wrong...?

**firebio** · Dec 21st 2009, 08:21 PM

Originally Posted by ninjuhtime

x = 88 in radians
am i right?

or is it: x = 137.09 in degrees?
yea, haha.

does x = 88 ?
or is my answer wrong...?

I got x = 137
88 is wrong because u r not working in radians

**ninjuhtime** · Dec 21st 2009, 08:23 PM

Originally Posted by firebio

I got x = 137
88 is wrong because u r not working in radians

oh, thank you. (:
no wonder i got it wrong... i'm suppose to use degrees not radians... haha...

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