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Math Help - Trig question?

  1. #1
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    Trig question?

    How do I solve this?
    Given tan(\pi-t)=10 tind tan t

    I have no clue where to start.
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  2. #2
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    Quote Originally Posted by dorkymichelle View Post
    How do I solve this?
    Given tan(\pi-t)=10 tind tan t
    I have no clue where to start.

     \tan(\pi-t)= \frac{\tan\pi - \tan t}{1+\tan\pi\tan t} = <br />
\frac{0-\tan t}{1+0} = -\tan t


    Therefore,  \tan(\pi-t)=10 \implies \tan t = -10 .


    Another way to tackle this is using arctan, but using properties has its advantages.

    -Andy
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