How do I solve this? Given $\displaystyle tan(\pi-t)=10$ tind $\displaystyle tan t$ I have no clue where to start.
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Originally Posted by dorkymichelle How do I solve this? Given $\displaystyle tan(\pi-t)=10$ tind $\displaystyle tan t$ I have no clue where to start. $\displaystyle \tan(\pi-t)= \frac{\tan\pi - \tan t}{1+\tan\pi\tan t} = \frac{0-\tan t}{1+0} = -\tan t $ Therefore, $\displaystyle \tan(\pi-t)=10 \implies \tan t = -10 $. Another way to tackle this is using arctan, but using properties has its advantages. -Andy
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