If A = 18degrees, b - a =2, ab =4, using the usual notation fora triangle, use the sine rule to find B.
Help I keep getting this q wrong in my book it says the answer is 53.85, but i keep getting like 53.999.
Solve the simultaneous equations for a and b
$\displaystyle a = -1+ \sqrt{5}$ : $\displaystyle b = 1+\sqrt{5}$
$\displaystyle \frac{sinA}{a} = \frac{sinB}{b}$
$\displaystyle B = arcsin \left(\frac{b}{a}sinA\right) = arcsin \left(\frac{1+\sqrt5}{1-\sqrt5}sin(18)\right) = $
How odd, I get -54 exactly