# Thread: Finding area and angle of triangle

1. ## Finding area and angle of triangle

In the usual notation for a triangle, b =6 cm, c =10cm and B = 30degrees.
Show that there are two possible values for C, and find the area of the triangle in each case.

I dont get how there are 2 values for C. I've used the sin rule to get C 47.83degrees. How do I do this?
thanks

2. Originally Posted by Detanon
In the usual notation for a triangle, b =6 cm, c =10cm and B = 30degrees.
Show that there are two possible values for C, and find the area of the triangle in each case.

I dont get how there are 2 values for C. I've used the sin rule to get C 47.83degrees. How do I do this?
thanks
Hint for two possible values for C: $\sin (\pi - \theta) = \sin \theta$

Hint for the area: Area $= \frac12 bc \sin A = \frac12 bc \sin (\pi - B - C)$