why is: $\displaystyle (tg x)^{sin x} = \frac{1}{(tg x)^{cos x}}$
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Originally Posted by metlx why is: $\displaystyle (tg x)^{sin x} = \frac{1}{(tg x)^{cos x}}$ The above equation is wrong. Try $\displaystyle x = \frac{\pi}3$ radians.
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