Math Help - trig equality

1. trig equality

why is:

$(tg x)^{sin x} = \frac{1}{(tg x)^{cos x}}$

2. Originally Posted by metlx
why is:

$(tg x)^{sin x} = \frac{1}{(tg x)^{cos x}}$
The above equation is wrong. Try $x = \frac{\pi}3$ radians.