Anyone know this one?
$\displaystyle f(x)=9x^3-48x^2+64x$
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Anyone know this one?
$\displaystyle f(x)=9x^3-48x^2+64x$
I did and when I did it I get stuck at $\displaystyle f(x)=x(9x^2-48x+64)$
Remember !
$\displaystyle (a-b)^2=a^2-2ab+b^2$
(Happy)
Ummm.. Sadly I do not understand it very well or how to get the zeros from it algebraically.
When I pluged it in I got 0=9 so would that mean that there is no zeros in the equation?