Originally Posted by

**Paymemoney** Hi

I am having trouble solving the following equation:

$\displaystyle tan(3x-\frac{\pi}{6})$

range $\displaystyle 0,2\pi$

this is what a have done, someone tell me where my mistake is.

$\displaystyle 3x-\frac{\pi}{6}=\pi-\frac{\pi}{6},2\pi-\frac{\pi}{6},3\pi-\frac{\pi}{6},4\pi-\frac{\pi}{6},5\pi-\frac{\pi}{6},6\pi-\frac{\pi}{6}$

$\displaystyle 3x=\frac{5\pi}{6}+\frac{\pi}{6},\frac{11\pi}{6}+\f rac{\pi}{6},\frac{17\pi}{6}+\frac{\pi}{6},\frac{23 \pi}{6}+\frac{\pi}{6},\frac{29\pi}{6}+\frac{\pi}{6 },\frac{35\pi}{6}+\frac{\pi}{6}$

$\displaystyle x=\frac{6\pi}{36},\frac{12\pi}{36},\frac{18\pi}{36 },\frac{24\pi}{36},\frac{30\pi}{36},\frac{26\pi}{3 6}$

P.S