I don't think any values can be found for example 2.
The first example has a right angle and you don't want to use more complicated methods than is necessary so the Pythagoras theorem will do or the basic trigonometrical ratios.
Can you tell me how to find the sides of he triangles in Q1 and Q2 in the attached drawing
they are right angled triangles
in question 2 i found that a=1.9 and b=1.3 using Soh
but i want to know If i can use
I want to be able to use other forumlas than a^2 + b^2=c^2
Please help thanks
The angle B in question 2 is 34 degrees
Please tell me how to calculate the answers for the two questions,I have an important exam next week, can it be done with the other formula in my original post?I can seem to do them with that?is that formula only for triangles that are not 90*
which, I would have thought, provides the necessary justification.It's an isosceles triangle
Alternatively, use Pythagoras' Theorem. Alternatively, use (which you should have realised from what I posted about question 2).
Why are you insisting on wanting to use the cosine rule? For a right angle triangle A = 90 degrees and it's just Pythagoras' Theorem. The cosne rule and the sine rule are used when you have a triangle that is NOT a right-triangle. You should know that.
Here are links to tutorials for basic "right angle" trig, with a very DIFFERENT approach than the usuals "soh cah toa" mneumonic. The first shows you how to make a "Trig Tool", which elimininates memorizing a lot of formulas, the next two show you how to USE it.
How to Memorize the Trig Functions (Without Losing Your Mind!) | eHow.com
How to Pass That Trigonometry Exam (Without Losing Your MIND!) Part I - Unknown Sides | eHow.com
How to Pass That Trigonometry Exam (Without Losing Your MIND!) Part II - Unknown Angles | eHow.com