Trig Question

**Paymemoney** · December 9th 2009, 06:05 PM

Hi
I am having trouble understanding what i am meant to do in the following question:

Find all values of x between 0 and $2\pi$ for which
$sin x =0.6$

P.S

**mr fantastic** · December 9th 2009, 06:08 PM

Originally Posted by Paymemoney

Hi
I am having trouble understanding what i am meant to do in the following question:

Find all values of x between 0 and $2\pi$ for which
$sin x =0.6$

P.S

Use the symmetry of the unit circle: $x = \sin^{-1} 0.6$ and $x = \pi - \sin^{-1} 0.6$ .

**Paymemoney** · December 9th 2009, 06:15 PM

can this is done without using the calculator??

**mr fantastic** · December 9th 2009, 06:19 PM

Originally Posted by Paymemoney

can this is done without using the calculator??

Of course. See my answer!

However, if you want a value of $\sin^{-1} 0.6$ then of course you will have to use a calculator to get a decimal approximation.

**Vesicant** · December 12th 2009, 11:39 AM

Once you have gotten you approximation which will be in degrees you need to convert your degrees to radians using:

$Degrees X Pi/180$

Then you'll need to write your notation.

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