my ugly attempt

/edit got another step

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- December 8th 2009, 08:23 PMdorkymichelleHelp solving trig equation 1
my ugly attempt

/edit got another step

- December 8th 2009, 08:43 PMbigwaverecall that
- December 8th 2009, 08:52 PMdorkymichelle
I ended up with

what is the next methodlical step?(i can't spell..)

In the answers, it is (its a study guide for my next test)

How can I solve an equation without a basic unit circle trig. value? - December 8th 2009, 10:11 PMbigwave
- December 9th 2009, 07:24 PMdorkymichelle
Thankyou!

- December 9th 2009, 07:35 PM11rdc11
- December 9th 2009, 08:19 PMdorkymichelle
hmm.. if I also use 3\pi/4 then x would = to 3\pi/8 +n\pi, that is on the answer, but \pi/8 +n\pi is not on the answer.

And also, I don't understand how you get 9\pi/8?

Did he just skip the 2st quadrant, and wrote the 2nd answer as going half a circle from the 2nd quadrant instead of using the answer from the 1st? - December 9th 2009, 08:24 PM11rdc11
- December 9th 2009, 08:31 PMdorkymichelle
So basicly, if I put \pi/8,3\pi/8 and 9\pi/8 they will all be correct answers?

- December 9th 2009, 08:37 PM11rdc11
- December 9th 2009, 09:00 PMdorkymichelle
The question told me to find all solutions

The teacher's answer on the study guide is

so I guess both ways is correct, but my teacher is just picky about solutions? - December 9th 2009, 09:52 PM11rdc11
- December 9th 2009, 10:08 PMdorkymichelle
Thankyou so much. i fainlly understand this. The differnt answers were confusing me day.

- December 9th 2009, 10:15 PM11rdc11