Im doing a math problem and I get this far. $\displaystyle \frac{sin^2Psin^2P}{cos^2P} $ Can that be converted to $\displaystyle tan^2Psin^2P$? Thanks!
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Originally Posted by Godzilla Im doing a math problem and I get this far. $\displaystyle \frac{\sin^2(P) \sin^2(P)}{\cos^2(P)}$ Can that be converted to $\displaystyle \tan^2(P) \sin^2(P)$? Thanks! $\displaystyle \dfrac{\sin(P)}{\cos(P)} = \tan(p)$ $\displaystyle \frac{\sin^2(P) \sin^2(P)}{\cos^2(P)} = \dfrac{\sin^2(P)}{\cos^2(P)} \cdot \sin^2(P) = \tan^2(P) \sin^2(P)$
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