Can someone just get me started on this problem? Thanks.
2cos(theta)-sin2(theta)=0
I tried to substitute 2sin(theta)cos(theta) for the sin2(theta), but that didn't really get me anywhere.
$\displaystyle 2\cos(\theta)-\sin(2\theta)=0$
$\displaystyle 2\cos(\theta)-2\sin(\theta)\cos(\theta)=0$
now factor and divide
$\displaystyle 2\cos(\theta)(1-\sin(\theta))=0$
$\displaystyle 1-\sin(\theta)=0$
$\displaystyle \sin(\theta)=1$
Can you solve it now?