Solve the following equations given that $\displaystyle 0 \leq x \leq 2\pi$.

$\displaystyle a) \cos^2x - \sin^2x = 1$

$\displaystyle b) 1 + \sqrt{3}\tan2x = 0$

Your help is really appreciated. Thanks.

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- Dec 3rd 2009, 09:48 AMSavior_SelfSolving with Trig Identities..
Solve the following equations given that $\displaystyle 0 \leq x \leq 2\pi$.

$\displaystyle a) \cos^2x - \sin^2x = 1$

$\displaystyle b) 1 + \sqrt{3}\tan2x = 0$

Your help is really appreciated. Thanks. - Dec 3rd 2009, 10:09 AMLight
$\displaystyle a) \cos^2x - \sin^2x = 1$

$\displaystyle b) 1 + \sqrt{3}\tan2x = 0$

Your help is really appreciated. Thanks.[/quote]

a) Replace sin^2 X by 1-cos^2 X.

The equation becomes 2cos^2 X =2 - Dec 3rd 2009, 10:14 AMLight