I usually post my questions in advance, but this weekend I got busy, so sorry for the rush. Solve for x: 3tan^2(x) - 1 = 0 Thanks, Mr. Green
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Hello, Mr_Green! Solve for x: .3·tanČ(x) - 1 .= .0 We have: .3·tanČ(x) .= .1 . . .Then:. . .tanČ(x) .= .1/3 . . . . . . . . . . . . . . . . . . . . ._ . .Hence: . . . tan(x) .= .±1/√3 Therefore: .x .= .±π/6, ±5π/6.
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