Originally Posted by

**snypeshow** Hey guys!

So for an assignment, we're given some trig functions and asked to graph it, from it's base graph to it's final state: but i'm having problems with these two:

**b) y = 3cos2x + 1 for 0 **__<__ x __<__ 360°

**d) y = -sin(x/3) - 2 for -pi/2 **__<__ x __<__ pi/2

**Solution for b):**

So I know the base graph is y=cos(x), so the first graph I draw is y=cos(x). The second graph would be y=cos(x) but all the x-values are multiplied by 3. *I don't know what to do with the 2x part*. The last graph would be the whole thing, shifted up one unit.

**Solution for d):**

The base graph is y=sin(x), so the first graph to draw is sin(x). The second graph to draw is -sin(x), which is basically sin(x) flipped on the x-axis. *I don't know what to do for the (x/3) part.* The last graph would be the whole thing shifted downwards.

the parts i'm not sure what to do is the ones italicized above. Any help would be appreciated !