Originally Posted by
snypeshow Hey guys!
So for an assignment, we're given some trig functions and asked to graph it, from it's base graph to it's final state: but i'm having problems with these two:
b) y = 3cos2x + 1 for 0 < x < 360°
d) y = -sin(x/3) - 2 for -pi/2 < x < pi/2
Solution for b):
So I know the base graph is y=cos(x), so the first graph I draw is y=cos(x). The second graph would be y=cos(x) but all the x-values are multiplied by 3. I don't know what to do with the 2x part. The last graph would be the whole thing, shifted up one unit.
Solution for d):
The base graph is y=sin(x), so the first graph to draw is sin(x). The second graph to draw is -sin(x), which is basically sin(x) flipped on the x-axis. I don't know what to do for the (x/3) part. The last graph would be the whole thing shifted downwards.
the parts i'm not sure what to do is the ones italicized above. Any help would be appreciated !