Results 1 to 4 of 4

Math Help - Trig

  1. #1
    Newbie
    Joined
    Nov 2009
    Posts
    23

    Trig

    Find A values

    csc (
    6a +π/8)=sec (2a -π/8).

    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Nov 2009
    Posts
    202

    quite lengthy!!!

    cosec(6a+pi/8)=sec(2a-pi/8)
    =>sin(6a+pi/8)=cos(2a-pi/8)
    =>sin(6a+pi/8)=sin(pi/2-2a+pi/8)
    =>6a+pi/8=5pi/8-2a
    =>8a=4pi/8
    =>a=pi/4=the principal value

    it becomes lengthy for integral values.the answer is

    a=1/3*n*pi+pi/16 where n belongs to integral values.please comment!!
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by Pulock2009 View Post
    cosec(6a+pi/8)=sec(2a-pi/8)
    =>sin(6a+pi/8)=cos(2a-pi/8)
    =>sin(6a+pi/8)=sin(pi/2-2a+pi/8)
    =>6a+pi/8=5pi/8-2a
    =>8a=4pi/8
    =>a=pi/4=the principal value

    it becomes lengthy for integral values.the answer is

    a=1/3*n*pi+pi/16 where n belongs to integral values.please comment!!
    If \sin A = \sin B then either A = B + 2n \pi or A = \pi - B + 2n\pi where n is an integer ....
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member mrmohamed's Avatar
    Joined
    Dec 2009
    From
    Egypt
    Posts
    43

    Lightbulb

    Quote Originally Posted by Tiger View Post
    Find A values


    csc (6a +π/8)=sec (2a -π/8).
    Hi all
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Compute Trig Function Values, Solve Trig Equation
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: September 8th 2011, 07:00 PM
  2. Replies: 7
    Last Post: April 15th 2010, 08:12 PM
  3. Replies: 6
    Last Post: November 20th 2009, 04:27 PM
  4. Replies: 1
    Last Post: July 24th 2009, 02:29 AM
  5. Replies: 2
    Last Post: April 21st 2006, 03:04 PM

Search Tags


/mathhelpforum @mathhelpforum