just need some help getting started 1.) sin2x= -1/2 2.) 4cos^2 x-8cosx+1=0 3.) sin2x= -sinx greatly appreciate it
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Originally Posted by zukywich08 just need some help getting started 1.) sin2x= -1/2 2.) 4cos^2 x-8cosx+1=0 3.) sin2x= -sinx greatly appreciate it (1) $\displaystyle sin(u) = -\frac{1}{2}$ $\displaystyle u = \frac{7\pi}{6} \, , \, \frac{11\pi}{6}$ and those angles coterminal with these two. (2) quadratic formula ... (3) $\displaystyle 2\sin{x}\cos{x} + \sin{x} = 0$ factor and solve
for the third problem how would you factor it? do you take sinx out of it?
Originally Posted by zukywich08 for the third problem how would you factor it? do you take sinx out of it? yes
i got sinx(sinxcosx+1)=0 but i dont know what to do with the cosine?
Originally Posted by zukywich08 i got sinx(sinxcosx+1)=0 but i dont know what to do with the cosine? review your algebra ... $\displaystyle 2\sin{x}\cos{x} + \sin{x} = 0$ $\displaystyle \sin{x}(2\cos{x} + 1) = 0$ set each factor = 0 and solve
alright thanks for the help man it came in handy
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