1. ## Trig graphing(I think)

I think I'm suppose to graph these but I don't know how

1) Y=5sin1/3x

2) Y=Sin2x-4

3) Y=1/2Sin2(X-90degrees)+1

4) Y=Sin(3x-120)+1

5) Y=4Sin(1/2x+30degrees)-1

Can anyone help me?

2. Originally Posted by Draft
I think I'm suppose to graph these but I don't know how

1) Y=5sin1/3x

2) Y=Sin2x-4

3) Y=1/2Sin2(X-90degrees)+1

4) Y=Sin(3x-120)+1

5) Y=4Sin(1/2x+30degrees)-1

Can anyone help me?
HI

There are too many questions here . I will do 1 and 2 and you will try the rest . Ok ?

For (1) , always refer to the original sin graph , $\displaystyle y=\sin \theta$ . Note that For all sin graph here , it will start from 0 and end at 360 .

One cycle here is $\displaystyle 360^o$ . 1/3 of the cycle would be $\displaystyle 120^o$ so your graph should stop at $\displaystyle 120^o$ . Then label this $\displaystyle 120^o$ as $\displaystyle 360^o$ . Notice that the amplitude is 5.

For (2) , sin 2x : this will go 2 rounds . -4 : shift the graph downwards for 4 .

HI

There are too many questions here . I will do 1 and 2 and you will try the rest . Ok ?

For (1) , always refer to the original sin graph , $\displaystyle y=\sin \theta$ . Note that For all sin graph here , it will start from 0 and end at 360 .

One cycle here is $\displaystyle 360^o$ . 1/3 of the cycle would be $\displaystyle 120^o$ so your graph should stop at $\displaystyle 120^o$ . Then label this $\displaystyle 120^o$ as $\displaystyle 360^o$ . Notice that the amplitude is 5.

For (2) , sin 2x : this will go 2 rounds . -4 : shift the graph downwards for 4 .