Find, to the nearest degree, all values of theta in the interval 0° ≤ theta < 360°

that satisfy the equation 3 cos 2theta + sin theta – 1 = 0.

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- Nov 24th 2009, 10:10 AMblame_canada100Solving a trig equation
Find, to the nearest degree, all values of theta in the interval 0° ≤ theta < 360°

that satisfy the equation 3 cos 2theta + sin theta – 1 = 0. - Nov 24th 2009, 11:43 AMapcalculus
At:

**Wolfram|Alpha**

enter the command:

**plot 3 cos(2x) + sin(2x) - 1 for x between 0 and 360 degrees**

it looks like the equation has four zeros in your interval. Use your graphing calculator to approximate them.

Good luck! - Nov 24th 2009, 01:39 PMSoroban
Hello, blame_canada100!

Quote:

Find, to the nearest degree, all values of in the interval

that satisfy the equation: .

The equation becomes: .

Factor: .

And we have two equations to solve:

. .

. .