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Thread: Solving trig equation...

  1. #1
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    Solving trig equation...

    I am trying to do this problem and I only get so far.

    $\displaystyle 2 sin3x+1=0$

    Thanks in advance.
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  2. #2
    Senior Member
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    break the problem down

    So what z solves?

    $\displaystyle
    2 z +1=0
    $

    Then what y solves
    $\displaystyle
    sin y = z
    $

    Then what x solves
    $\displaystyle
    3x = y
    $
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  3. #3
    Junior Member mrmohamed's Avatar
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    Quote Originally Posted by Godzilla View Post
    I am trying to do this problem and I only get so far.

    $\displaystyle 2 sin3x+1=0$

    Thanks in advance.
    hi all
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  4. #4
    Super Member
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    Africa
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    Smile


    Put $\displaystyle sin(3x)=y$
    and solve for $\displaystyle y$,the equation $\displaystyle 2y+1=0$.
    Remember,$\displaystyle sin(-\frac{\pi }{6})=-\frac{1}{2}$.
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