1. ## Solving trig equation...

I am trying to do this problem and I only get so far.

$2 sin3x+1=0$

2. ## break the problem down

So what z solves?

$
2 z +1=0
$

Then what y solves
$
sin y = z
$

Then what x solves
$
3x = y
$

3. Originally Posted by Godzilla
I am trying to do this problem and I only get so far.

$2 sin3x+1=0$

4. Put $sin(3x)=y$
and solve for $y$,the equation $2y+1=0$.
Remember, $sin(-\frac{\pi }{6})=-\frac{1}{2}$.