Let x be in the 2nd quadrant such that sin(x) = a. Evaluate the expression in terms of a Cos^2(arcsin(a)) Any help?
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$\displaystyle cos^2\theta=1-sin^2\theta$ Sooooooooo... $\displaystyle cos^2(arcsin(a))=1-sin^2(arcsin(a))$ Should be solvable from there Last hint: $\displaystyle sin(arcsin\theta)=\theta$
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