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Thread: Trig expression

  1. November 22nd 2009, 06:20 PM #1
    VkL
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    Trig expression

    Let x be in the 2nd quadrant such that sin(x) = a.

    Evaluate the expression in terms of a

    Cos^2(arcsin(a))

    Any help?
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  2. November 22nd 2009, 06:29 PM #2
    I-Think
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    cos^2\theta=1-sin^2\theta

    Sooooooooo...

    cos^2(arcsin(a))=1-sin^2(arcsin(a))

    Should be solvable from there

    Last hint: sin(arcsin\theta)=\theta
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