Solve (-2pi , 2pi) what trig identities do you use?
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Originally Posted by VkL Solve (-2pi , 2pi) what trig identities do you use? most important one you need to use ... $\displaystyle \cos^2(u) + \sin^2(u) = 1$
and what do you do with the tangent?
Originally Posted by VkL and what do you do with the tangent? $\displaystyle \tan\left(\frac{x}{2}\right) = 1$ you solve the equation.
Oh, Ok I see, How you got that. But I still cannot solve it? I got it down to sin(x/2)-Cos(x/2) = 0
Originally Posted by VkL Oh, Ok I see, How you got that. But I still cannot solve it? I got it down to sin(x/2)-Cos(x/2) = 0 ... where does $\displaystyle \sin\left(\frac{x}{2}\right) = \cos\left(\frac{x}{2}\right)$ in the given interval?
Pi/2 ??
Originally Posted by VkL Pi/2 ?? that's one of the solutions in the interval ... there is another.
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