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Math Help - Trig equation

  1. #1
    VkL
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    Trig equation

    Solve (-2pi , 2pi)



    what trig identities do you use?
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  2. #2
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    Quote Originally Posted by VkL View Post
    Solve (-2pi , 2pi)



    what trig identities do you use?
    most important one you need to use ...

    \cos^2(u) + \sin^2(u) = 1
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  3. #3
    VkL
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    and what do you do with the tangent?
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  4. #4
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    Quote Originally Posted by VkL View Post
    and what do you do with the tangent?
    \tan\left(\frac{x}{2}\right) = 1

    you solve the equation.
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  5. #5
    VkL
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    Oh, Ok I see, How you got that.

    But I still cannot solve it?

    I got it down to sin(x/2)-Cos(x/2) = 0
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  6. #6
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    Quote Originally Posted by VkL View Post
    Oh, Ok I see, How you got that.

    But I still cannot solve it?

    I got it down to sin(x/2)-Cos(x/2) = 0
    ... where does \sin\left(\frac{x}{2}\right) = \cos\left(\frac{x}{2}\right) in the given interval?
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  7. #7
    VkL
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    Pi/2 ??
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  8. #8
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    Quote Originally Posted by VkL View Post
    Pi/2 ??
    that's one of the solutions in the interval ...

    there is another.
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