# Thread: trig equation from 0<t<2pi

1. ## trig equation from 0<t<2pi

solve 3sin(2t+1) = -0.8142 from 0<t<2pi

please show working as I need to know how these answers where found

1.21 2.51 4.35 5.65

I dont really understand what 3sin(2t+1) means

2. Originally Posted by davyboy123
solve 3sin(2t+1) = -0.8142 from 0<t<2pi

please show working as I need to know how these answers where found

1.21 2.51 4.35 5.65

I dont really understand what 3sin(2t+1) means
HI

The range required is $0

$3\sin (2t+1)=-0.8142$

2t+1=3.416 , 6.008 , 6.558 , 9.15 (all in radians)

Since sin is negative here , so t would be in the 3rd and fourth quadrant . I am sure you know this .

THen now , just do the algebra or in other words solve for t and you would get the answers .