Hello, Mike!
Find an equation in x and y for the conic section with polar equation:
. . . . . . . . . 1
. . r .= . -----------
. . . . . . 1 + cos θ
Possible answers:
. . y² .= .1 - 2x . . x² - x + y² .= .1 . . x² + y² .= .1 . . x² + x - y .= .1
We have: .r(1 + cosθ) .= .1
. . . . . . . . .r + r·cosθ .= .1
. . . . . . . . . . . . . . .r .=] .1 - r·cosθ
. . . . . . . . . . ______
Convert: . . .√x² + y² .= .1 - x
Square: . . . . .x² + y² .= .1 - 2x + x²
Therefore: . . . . . . y² .= .1 - 2x
(Dan, you got a unit circle. .That equation would be: r = 1)