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Math Help - Triangle help - trigonometry

  1. #1
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    Triangle help - trigonometry

    A vertical pole 34 feet tall on a hillside that makes an angle of 13 degree with the horizontal. Determine the approximate length of a cable that would be needed to reach from the top of the pole to a point 57 feet downhill from the base of the pole.
    Last edited by mr fantastic; November 17th 2009 at 03:26 PM. Reason: Removed gratuitious symbols in post title
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  2. #2
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    Quote Originally Posted by refresh View Post
    A vertical pole 34 feet tall on a hillside that makes an angle of 13 degree with the horizontal. Determine the approximate length of a cable that would be needed to reach from the top of the pole to a point 57 feet downhill from the base of the pole.
    #1 Draw a sketch.
    A rough sketch will often clear the fog.

    The assumption is that the "57 feet downhill" is measured along the slope of the ground (and not horizontally from the base of the pole.)

    The "point" will be
     57 \sin(13deg) = 12.8 feet BELOW the base of the pole; add that to the 34 feet to get the altitude of the triangle.
    &
     57 \cos(13deg) = 55.5 feet away from the center of the vertical pole; this is the base of the triangle.
    then
    the length of cable required =  \sqrt{ (34+12.8)^2 + (55.5)^2} is the hypotenuse of the triangle.

    Does that help?
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