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Thread: Finding domain for inverse trig.

  1. November 15th 2009, 05:17 PM #1
    xwrathbringerx
    xwrathbringerx is offline
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    Exclamation Finding domain for inverse trig.

    2arcsin(x*sqrt(6)) + arcsin(4x) = pi/2

    When you solve for x, you get several solutions. Could someone please show me how to find the domain for x in order to get the right answers?
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  2. November 15th 2009, 05:28 PM #2
    douber
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    -1/4 < x < 1/4

    because anything outside that... the function is undefined
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