I have this od chestnut to solve, I have done as much as what I think is right but I need some assistance:

a) A body of mass m kg is attached to a point by string of length

1.25 m. If the mass is rotating in ahorizontalcircle0.75 m below the

point of attachment, calculate its angular velocity.

So far I have:

$\displaystyle r = \sqrt{1.25^2 - 0.75^2}$

$\displaystyle r = 1$

$\displaystyle \tan\theta = \frac{\omega^2r}{g}$

$\displaystyle \tan\theta = \frac{1}{0.75}$

$\displaystyle therefore:$

$\displaystyle 53.13 = \frac{\omega^2}{9.81}$

$\displaystyle \omega = 22.83$

Have I totally done this wrong, also were do I need to go from here?

Thanks