Solve the Equation for A between 0 and 360 inclusive, giving non-exact answers. In each case use trigonometric identities. a) cos2A +3 +4cosA=0 b) 2cos 2A+1+ sinA= 0 THANKS!
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Originally Posted by Oasis1993 Solve the Equation for A between 0 and 360 inclusive, giving non-exact answers. In each case use trigonometric identities. a) cos2A +3 +4cosA=0 b) 2cos 2A+1+ sinA= 0 THANKS! HI (1) $\displaystyle 2\cos^2 A-1+4\cos A+3=0$ $\displaystyle 2\cos^2 A+4\cos A+2=0$ $\displaystyle \cos^2 A+2\cos A+1=0$ $\displaystyle \cos A=-1$ go on .... (2) $\displaystyle 2(1-\sin^2 A)+1+\sin A =0$
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