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Math Help - Trigonometry help plz!!!

  1. #1
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    Question Trigonometry help plz!!!

    the question says:

    Given that arctan(x-2)= -π/3 find the value of x.

    I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by ladythugette View Post
    the question says:

    Given that arctan(x-2)= -π/3 find the value of x.

    I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense
    Hi ladythugette,

    \arctan x = y means x = \tan y

    \arctan (x-2)=-\frac{\pi}{3} means x-2=\tan -\frac{\pi}{3}

    x=\tan\left(-\frac{\pi}{3}\right)+2
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  3. #3
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    Quote Originally Posted by masters View Post
    Hi ladythugette,

    \arctan x = y means x = \tan y

    \arctan (x-2)=-\frac{\pi}{3} means x-2=\tan -\frac{\pi}{3}

    x=\tan\left(-\frac{\pi}{3}\right)+2
    I soooo get it.!!.it looks very simple the way you've explained it. Thank-You very much
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