the question says: Given that arctan(x-2)= -π/3 find the value of x. I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense
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Originally Posted by ladythugette the question says: Given that arctan(x-2)= -π/3 find the value of x. I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense Hi ladythugette, $\displaystyle \arctan x = y$ means $\displaystyle x = \tan y$ $\displaystyle \arctan (x-2)=-\frac{\pi}{3}$ means $\displaystyle x-2=\tan -\frac{\pi}{3}$ $\displaystyle x=\tan\left(-\frac{\pi}{3}\right)+2$
Originally Posted by masters Hi ladythugette, $\displaystyle \arctan x = y$ means $\displaystyle x = \tan y$ $\displaystyle \arctan (x-2)=-\frac{\pi}{3}$ means $\displaystyle x-2=\tan -\frac{\pi}{3}$ $\displaystyle x=\tan\left(-\frac{\pi}{3}\right)+2$ I soooo get it.!!.it looks very simple the way you've explained it. Thank-You very much
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