# Trigonometry help plz!!!

• Nov 10th 2009, 10:47 AM
Trigonometry help plz!!!
the question says:

Given that arctan(x-2)= -π/3 find the value of x.

I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense:confused:
• Nov 10th 2009, 11:30 AM
masters
Quote:

the question says:

Given that arctan(x-2)= -π/3 find the value of x.

I have no clue what to do...I'v tried tanx=x-2=-π/3 ..but it doesn't really make sense:confused:

$\arctan x = y$ means $x = \tan y$

$\arctan (x-2)=-\frac{\pi}{3}$ means $x-2=\tan -\frac{\pi}{3}$

$x=\tan\left(-\frac{\pi}{3}\right)+2$
• Nov 10th 2009, 11:39 AM
Quote:

Originally Posted by masters

$\arctan x = y$ means $x = \tan y$

$\arctan (x-2)=-\frac{\pi}{3}$ means $x-2=\tan -\frac{\pi}{3}$

$x=\tan\left(-\frac{\pi}{3}\right)+2$

I soooo get it.!!.it looks very simple the way you've explained it. Thank-You very much(Happy)