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Math Help - solving a trigonometric equation

  1. #1
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    solving a trigonometric equation

    this should be fairly easy, but I'm afraid as I'm at a loss as on how to solve this.

    sinx = cosx on an interval of 0 <= x < 2pi

    I can reason it out... since sin is opposite over hypotenuse and cos is adjacent over hypotenuse, this is only true where adjacent = opposite, making it \frac{\pi}{4} and \frac{5\pi}{4}.

    But how is the problem solved algebraically?
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  2. #2
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    Quote Originally Posted by satis View Post
    this should be fairly easy, but I'm afraid as I'm at a loss as on how to solve this.

    sinx = cosx on an interval of 0 <= x < 2pi

    I can reason it out... since sin is opposite over hypotenuse and cos is adjacent over hypotenuse, this is only true where adjacent = opposite, making it \frac{\pi}{4} and \frac{5\pi}{4}.

    But how is the problem solved algebraically?
    \frac{sin(x)}{cos(x)} = tan(x) = 1

    This is undefined for x = \frac{\pi}{2}
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  3. #3
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    Oh, that was simple. Thank you.
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