solve the following for x: 2sin^2=1 (0 < x < 2*%pi) what is the solution set?? i think there are 4 answers to this , but im not sure how to do this.....
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Originally Posted by samtheman17 solve the following for x: 2sin^2=1 (0 < x < 2*%pi) what is the solution set?? i think there are 4 answers to this , but im not sure how to do this..... Do you mean ? If so Solve the equation, and then restrict the infinite amount of solutions to the given interval. It's lookin like
Last edited by VonNemo19; Nov 7th 2009 at 05:13 PM.
okay thanks, but how do you solve this equation?
Originally Posted by samtheman17 okay thanks, but how do you solve this equation?
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