solve the following for x:

2sin^2=1 (0 < x < 2*%pi)

what is the solution set??

i think there are 4 answers to this , but im not sure how to do this.....

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- Nov 7th 2009, 03:46 PMsamtheman17solving for x
solve the following for x:

2sin^2=1 (0 < x < 2*%pi)

what is the solution set??

i think there are 4 answers to this , but im not sure how to do this..... - Nov 7th 2009, 03:58 PMVonNemo19
- Nov 7th 2009, 04:02 PMsamtheman17
okay thanks,

but how do you solve this equation? - Nov 7th 2009, 04:13 PMVonNemo19