I was able to do with the brute force way, that is, multiply everything out then use the identity: to reduce everything to: My question is: is there a more elegant way to do this that doesn't take 5 YEARS.
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Does this help?
Hmm that looks interesting You got that from here: List of trigonometric identities - Wikipedia, the free encyclopedia right? I was browsing that earlier and looked over it. Thank you sir!
Yeah I got it from wiki. Couldn't bear to type up so much.
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