(1/1-sinx)-(1/1+sinx)=2sectan i got stumped on this one
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Originally Posted by valvan (1/1-sinx)-(1/1+sinx)=2sectan i got stumped on this one $\displaystyle \frac{1}{1-sinx}-\frac{1}{1+sinx}$ = $\displaystyle \frac{2sinx}{1-sin^2x}$ = $\displaystyle \frac{2sinx}{cos^2x}$ = $\displaystyle 2\frac{1}{cosx}\frac{sinx}{cosx}$ = $\displaystyle 2secxtanx$
can you explain further how you got to =
Originally Posted by valvan can you explain further how you got to = HI $\displaystyle \frac{1}{1-sinx}-\frac{1}{1+sinx}$ Just combine the fractions . $\displaystyle \frac{1+\sin x}{(1-\sin x)(1+\sin x)}-\frac{1-\sin x}{(1+\sin x)(1-\sin x)}$
= Numerator/Denomenator Numerator = (1 + sin x) - (1 - sin x) = 1 + sin x - 1 + sin x = ?
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