I was wondering if I did it right:
2sin[4x+pi]+3
A=2
B=pi/2
C=pi/4
D=3
-3cos((x/2)+2pi))-5
A=-3
B=4pi
C=0
D=-5
a few things to remember
Amplitude is never negative (it's an absolute value)
the period of a sin and cos is 2pi / B. Same for sec and csc,
vertical shift is the number that's outside (you got that right in these cases)
horizontal shift is -C/B if I'm not mistaken.