OP and OQ are radii of length r cm of a circle centred at O.
The arc PQ of the circle subtends an angle of theta radians at O and the perimeter of the sector OPQ is 12 cm.
Show that the are A cm squared of the sector is given by
A = 72 theta / (2 + theta)^2
Any help would be appreciated
to find dy / dx of (72 theta) / (2 + theta)^2
do i get rid of the fraction by multiplying 72 theta by (2 + theta)^2??
This may be completly wrong
I get 288theta + 288theta^2 + 78 theta^3
dy dx = 576theta + 234theta
I think this is just flat out WRONG.
Any help appreciated