# Thread: Urgent help with verifying trigonmetric identities

1. ## Urgent help with verifying trigonmetric identities

1/secxtanx = cscx - sinx

I've tried some ways and every way I do this, I keep ending up in a dead end. It's not only just this problem, there's more I have trouble with. So, if anyone out there has some useful tips and strategies for verifying these trigonometric identities. It would be much appreciated. Thank You.

So anyway, 1/secxtanx = cscx - sinx. Here's what I attempted to do:

1/secxtanx = cscx - sinx
1/(1/cosx)(sinx/cosx) = cscx-sinx
cosx cosx/sinx = cscx-sinx

Here's where I run into trouble. What do I do? Where did I go wrong? I've spent a long time trying to figure this out and I'd love some help right now. So if anyone could help me, thanks.

2. Originally Posted by lax600
1/secxtanx = cscx - sinx

I've tried some ways and every way I do this, I keep ending up in a dead end. It's not only just this problem, there's more I have trouble with. So, if anyone out there has some useful tips and strategies for verifying these trigonometric identities. It would be much appreciated. Thank You.

So anyway, 1/secxtanx = cscx - sinx. Here's what I attempted to do:

1/secxtanx = cscx - sinx
1/(1/cosx)(sinx/cosx) = cscx-sinx
cosx cosx/sinx = cscx-sinx

Here's where I run into trouble. What do I do? Where did I go wrong? I've spent a long time trying to figure this out and I'd love some help right now. So if anyone could help me, thanks.
You're on the right track. You have $\displaystyle \frac{\cos^2(x)}{\sin(x)}$ Use $\displaystyle \sin^2(x)+\cos^2(x)=1$ and substitute for cos^2(x). You'll get two terms and when you simplify you'll have your answer.

3. hint ...

$\displaystyle \cos{x}\cdot\cos{x} = \cos^2{x} = 1-\sin^2{x}$