Hi all,
sin330cos150 - cos390sin390 = 0
Prove:
What am I to do with this? Do I convert ll to the one function or......mmmm got nothing.
Any help would be appreciated.
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Hi all,
sin330cos150 - cos390sin390 = 0
Prove:
What am I to do with this? Do I convert ll to the one function or......mmmm got nothing.
Any help would be appreciated.
Remember that the trig functions are periodic.
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The other two values are:
If you don't see why these are true, look here: Trigonometric functions - Wikipedia, the free encyclopedia
Scroll down and look at the unit circle next to the paragraph "Unit-circle definitions"
so it would now look like....
sin330cos150 - cos390sin390 = 0
(- ½)(-√3/2) - ( ½)(√3/2) = 0
√3/2 / 2 - √3/2 / 2 = 0 which is true
Is this how i should set it out ?
(Yes)(Yes)
Yup