Originally Posted by

**RSDonovan** Hi!

Hope this is posted in the right section - if not please advise.

If there are 2 points, (x1 y1) and (x2 y2), the equidistant point is at the midpoint at location ((x1+x2)/2) ((y1+y2)/2)

eg if there are 2 points p and q at locations (1,2) and (3,0) the point equidistant is at (2,1) - the midpoint m

y

4 |

3 |

2 |p

1 | m

_ |__q_______ x

0 1 2 3 4

Suppose there are more than 2 points? Is there a formula for working out the point equidistant to the n points?

eg if there are 3 points p q r at locations (1,2) (3,0) and (3,2), the point equidistant is still at (2,1), but I can't see a way of computing this from the figures.

y

4 |

3 |

2 |p--r

1 | m

_ |__q_______ x

0 1 2 3 4 NB hyphens are spaces-board changes 2 spaces to 1

This is not a test question or homework crib - I am in my late fifties and just interested in mathematics!

The thought occured to me and I just cant see a solution for the general case Equidistant point of points (x1 y1) (x2 y2) (x3 y3) ... (xn yn)

Thanks in advance!