Easy enough but apparently my math tutor doesnt understand that I DONT GET IT.

Alright so ive been talking to my math tutor from the univ. about this single question for about a week now and i HAVE to get it done.

If $\displaystyle Tan\alpha = {- 7\over24} $ and $\displaystyle Cot\beta = {3\over4}$

For a second quadrant angle $\displaystyle \alpha$ and a third quadrant angle $\displaystyle \beta$

Have to find

$\displaystyle Sin(\alpha + \beta) , Cos (\alpha + \beta) , Tan (\alpha + \beta), Sin(\alpha - \beta) , Cos(\alpha - \beta) , Tan(\alpha - \beta)$

Re: Easy enough but apparently my math tutor doesnt understand that I DONT GET IT.

Re: Easy enough but apparently my math tutor doesnt understand that I DONT GET IT.

My suggestion would be at first stage forget the sign, just find the trig values. e.g., tan A = 7/24 we know that the hypotenuse will be 25. so we will get sin A = 7/25; cosA = 23/25, tan A = 7/24; cot A = 24/7, sec A = 24/25 and csec A = 25/7.

Now in second step see where that angle lies, in this case A lies in II quadrant, we know that in second quadrant sine and its reciprocal csec are positive and all rest are negative. Put signs accordingly and you have the result:

sin A = 7/25; cosA = - 23/25, tan A = - 7/24; cot A = - 24/7, sec A = - 24/25 and csec A = 25/7.