...I've been working through a tanget sum identity problem and I've mostly got it, except I've got the signs reversed. I was curious if someone could point out the mistake I made. I apologize for how long this is. All assistance is appreciated.
is in QIII
is in QII
sinA= so the hypotenuse is 5, the oppose side is -3, making the adacent side (negative) 4. Thus tan(A) = .
here is your mistake ... in quad III, tangent is positive
Can someone please point out my mistake?