trig

• October 20th 2009, 12:05 PM
trig
Find all values of theta in the interval 0<theta<360 that satisfy the equation.

3 tan^2 theta - 1=0
• October 20th 2009, 12:20 PM
craig
Quote:

If you move the 1 over to the right of your equation, divide by 3 and then square root you get $\tan{\theta} = \frac{\pm1}{\sqrt{3}}$.