Hi
I need to rearrange the following formula from I = f(A) to A = f(I)
The formula is :
tan(I) = sin(A)/(M+cos(A))
Can anyone tell me how I rearrange this to get A as a function of I.
Thanks
James
Hello, James!
I have a way . . . but it's really ugly . . .
The formula is: .
Can anyone tell me how to get as a function of ?
We have: .
.From , we have: .
Substitute: .
Square both sides: .
This simplifies to the quadratic: .
Quadratic Formula: .
. . . Good luck!
tan(I) = sin(A)/(M+cos(A))
we know for sin(X)/cos(X)=sin(Y)/cos(Y), then Y = X is one solution.
tan(I) = sin(A)/(M+cos(A)) is the same as
sin(I)/cos(I) = sin(A)/(M+cos(A))
so one solution by my guess would be.
I = inv.cos (M + cos A)
cos A + M = cos I
A = inv. cos (cos I - M)