im supposed to eliminate A from the pair of equations

x= sin2A

y= sec4A

ive learnt most trig identities i think, up to the double angle identities etc.

ive done several problems like this but here im really stuck(Headbang)

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- Oct 12th 2009, 01:07 AMfuror celticaparameter
im supposed to eliminate A from the pair of equations

x= sin2A

y= sec4A

ive learnt most trig identities i think, up to the double angle identities etc.

ive done several problems like this but here im really stuck(Headbang) - Oct 12th 2009, 02:40 AMMush
- Oct 12th 2009, 02:47 AMmr fantastic
- Oct 12th 2009, 04:07 AMfuror celtica
i passed through those already, including the sin2A double angle identity which i already figured might be totally irrelevant to this problem. but where do i go from cos4A? i really didnt need someone to repeat these identities to me. im actually stuck.

- Oct 12th 2009, 04:17 AMmr fantastic
Actually, I think you did need the identity being repeated to you. It was being brought to your attention because it is relevant to answering the question. The hope was that you would contemplate how it was linked to the question, see

$\displaystyle x = {\color{red}\sin (2A)}$

$\displaystyle y = \sec (4A) = \frac{1}{\cos (4A)} = \frac{1}{1 - 2 {\color{red}\sin^2 (2A)}}$

and then join the dots .... - Oct 12th 2009, 04:21 AMfuror celtica
maybe i just overestimated the difficulty of this problem cos it was the last of the section

anyway i sure know to whom i'll be running when i need help next time!(ironic)