Sin2x<Sinx so that x is between 0 and 2Pi

So

Sin2x-sinx=0

2sinx.cosx-sinx

sinx(2cosx-1)=0

Sinx=0 or cosx=1/2

x=0,Pi/3,Pi, 5Pi/3 and 2Pi

So how do I answer this question from here?

Should I just substitute a value between 0 and Pi/3, Pi/3 and Pi, Pi and 5Pi/3....... and see whether sin2x value is smaller than the sinx value?

Is this a good way to do it or can you suggest a more expedient method to answer this Q? My method is rather time consuming I think - wondering if there's a better methd