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Math Help - inverse trig function help,

  1. #1
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    inverse trig function help,

    Without using a calculator, work out, giving your answer in terms of  \pi , the value of;

     arctan ( -\frac{1}{\sqrt{3}} )

    I know how to work out arcsin and arccos, by looking at the x and y values on the unit circle, but how do I work out acrtan? because the way I understand it is that tan = sin/cos which is equal to y/x.

    Can someone please explain how to work this out?

    thanks.
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  2. #2
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    Quote Originally Posted by Tweety View Post
    Without using a calculator, work out, giving your answer in terms of  \pi , the value of;

     arctan ( -\frac{1}{\sqrt{3}} )

    I know how to work out arcsin and arccos, by looking at the x and y values on the unit circle, but how do I work out acrtan? because the way I understand it is that tan = sin/cos which is equal to y/x.

    Can someone please explain how to work this out?

    thanks.
    Solve \tan \theta = - \frac{1}{\sqrt{3}} where -\frac{\pi}{2} < \theta < 0.
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