How do I solve the following for y, where 0 is less than or equal to y and y is less than 360 degrees? 11sin^2y = 13 - 3sin^2y ? Thank you.
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$\displaystyle 11sin^{2}y=13-3sin^{2}y$ $\displaystyle 14sin^{2}y=13$ $\displaystyle sin^{2}y=\frac{13}{14}$ $\displaystyle siny=\sqrt{\frac{13}{14}}$ $\displaystyle y=sin^{-|}\sqrt{\frac{13}{14}}$ $\displaystyle y=74.5^o, 285.35^o$ Cheers!
Thanks! But how did you get 285.35 degrees?
Oops! That should be $\displaystyle 105.5^o$ Sorry for that mistake, misquoted an identity To get the second answer, use the identity: $\displaystyle sin\theta=sin(180-\theta)$ The identity I misquoted was: $\displaystyle sin(360-\theta)=-sin\theta$
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