solve it using technology ... even if you solve for either or by hand, you'll still need a calculator to find .
I found the force to be 6.36N. I found it using .In the figure a fastidious worker pushes directly along the handle of a mop with a force F. The handle is at an angle θ = 31.33° with the vertical, and 0.42 and 0.32 are the coefficients of static and kinetic friction between the head of the mop and the floor. Ignore the mass of the handle and assume that all the mop's mass m = 0.50 kg is in its head. If the mop head moves along the floor with a constant velocity, then what is F?
The next question asks
Show that if θ is less than a certain value θ0, then F (still directed along the handle) is unable to move the mop head. Find θ0.
I setup the equation .
Now I can't find a way to solve for .
Ok, I'll trust you that you got F right. Say its 6.36N, the driving force that pushes the mop forwards is the x component of F:
6.36N x sin(31.33) = 3.3N
so the equation is:
6.36N x sin(teta) = sum of sheer forces (static and kinetic forces)
When the 2 equal each other you are static, the mop doesn't move.
It makes sense... the more you decrease teta...the more you decrease the x component of F thats your driving force so you need to push harder on the mop. When teta is zero you are pushing into the ground so even if you suply an infinite force you will not move the mop.