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Math Help - another trigonometric inequality

  1. #1
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    another trigonometric inequality

    Find the set of values which satisfy the inequality sin x < sqrt{3} cos x
    for 0 \leq x \leq 360

    Ok , i solve it first

    sin x = sqrt{3} cos x

    tan x = sqrt{3}

    x= 60 , 240

    Then it has 4 subintervals ie 0 , 60 , 240 , 360

    And it tested each and got this solutin

    0 <= 60 and 240<x<=360

    Am i correct ?
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  2. #2
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    Quote Originally Posted by thereddevils View Post
    Find the set of values which satisfy the inequality sin x < sqrt{3} cos x
    for 0 \leq x \leq 360

    Ok , i solve it first

    sin x = sqrt{3} cos x

    tan x = sqrt{3}

    x= 60 , 240

    Then it has 4 subintervals ie 0 , 60 , 240 , 360

    And it tested each and got this solutin

    0 <= x < 60 and 240<x<=360

    Am i correct ?
    Yes (but a small correction of some typos is in red).
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