Find the set of values which satisfy the inequality sin x < sqrt{3} cos x

for $\displaystyle 0 \leq x \leq 360$

Ok , i solve it first

sin x = sqrt{3} cos x

tan x = sqrt{3}

x= 60 , 240

Then it has 4 subintervals ie 0 , 60 , 240 , 360

And it tested each and got this solutin

0 <= 60 and 240<x<=360

Am i correct ?